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13-9x^2=-12
We move all terms to the left:
13-9x^2-(-12)=0
We add all the numbers together, and all the variables
-9x^2+25=0
a = -9; b = 0; c = +25;
Δ = b2-4ac
Δ = 02-4·(-9)·25
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30}{2*-9}=\frac{-30}{-18} =1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30}{2*-9}=\frac{30}{-18} =-1+2/3 $
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